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Popular >

y^'(t)=(1+y)(3-y),y(0)=4

Solution

y^{^{'}} (t) = (1 + y) (3 - y), y (0) = 4

Solution

3 + 2 y - y^{2}

Solution steps

Find

(1 + y) (3 - y)

given

y (0) = 4

(1 + y) (3 - y) = (1 + y) (3 - y)

y : 4

y : 4

= (1 + y) (3 - y)

Expand

(1 + y) (3 - y) : 3 + 2 y - y^{2}

= 3 + 2 y - y^{2}

Popular Examples

(dy)/(dx)=0.04-y/(4320/7)

\frac{d y}{d x} = 0.04 - \frac{y}{\frac{4320}{7}}

(dy)/(dx)=(1+2x)sqrt(y)

\frac{d y}{d x} = (1 + 2 x) y

f (x) = f^{^{'}} (x)

1 + y^{2} + x y y^{^{'}} = 0

(dy)/(dx)=(1+y^2)tan(x),y(0)=sqrt(3)

\frac{d y}{d x} = (1 + y^{2}) tan (x), y (0) = 3

Frequently Asked Questions (FAQ)

What is the y^'(t)=(1+y)(3-y),y(0)=4 ?
The y^'(t)=(1+y)(3-y),y(0)=4 is 3+2y-y^2