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Popular >

x^2y^'-cos(2y)=1

Solution

x^{2} y^{^{'}} - cos (2 y) = 1

Solution

y = arctan (- \frac{2}{x} + c_{1}) + πn

Solution steps

x^{2} y^{'} (x) - cos (2 y) = 1

Solve separable ODE:

y = arctan (- \frac{2}{x} + c_{1}) + πn

y = arctan (- \frac{2}{x} + c_{1}) + πn

Popular Examples

(1+x^2)(dy)/(dx)+2xy=x

(1 + x^{2}) \frac{d y}{d x} + 2 x y = x

y^'-6y=0,y(-1)=10

y^{^{'}} - 6 y = 0, y (- 1) = 10

(dy)/(dx)=-(x+xy^2)/(y+x^2y)

\frac{d y}{d x} = - \frac{x + x y ^{2}}{y + x ^{2} y}

(4x^2y^2-x^2+4xy^2-x)dx+(2xy+x+2y+1)dy=0

(4 x^{2} y^{2} - x^{2} + 4 x y^{2} - x) d x + (2 x y + x + 2 y + 1) d y = 0

(dy)/(dx)=(3y)/(x^6)

\frac{d y}{d x} = \frac{3 y}{x ^{6}}

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'-cos(2y)=1 ?
The solution for x^2y^'-cos(2y)=1 is y=arctan(-2/x+c_{1})+pin