What is the solution for (dy)/(dt)+20y=24,y= 6/5-6/5 e^{-20t} ?

The solution for (dy)/(dt)+20y=24,y= 6/5-6/5 e^{-20t} is y=-(e^{-20t-c_{1}})/5+6/5

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(dy)/(dt)+20y=24,y= 6/5-6/5 e^{-20t}

\frac{d y}{d t} + 20 y = 24, y = \frac{6}{5} - \frac{6}{5} e^{- 20 t}

y = - \frac{e ^{- 20 t - c_{1}}}{5} + \frac{6}{5}

Solution steps

\frac{d y}{d t} + 20 y = 24

Solve separable ODE:

y = - \frac{e ^{- 20 t - c_{1}}}{5} + \frac{6}{5}

y = - \frac{e ^{- 20 t - c_{1}}}{5} + \frac{6}{5}

d y = 1 - 4 y^{2} d x

y^{^{'}} = cos (x) tan (y)

\frac{d y}{d t} = \frac{t e ^{t}}{y 1 + y ^{2}}

y e^{y} d y + x d x = 0

\frac{d y}{d x} = \frac{2 x}{- 8 y - 10}, y (0) = - 8

What is the solution for (dy)/(dt)+20y=24,y= 6/5-6/5 e^{-20t} ?
The solution for (dy)/(dt)+20y=24,y= 6/5-6/5 e^{-20t} is y=-(e^{-20t-c_{1}})/5+6/5