What is the solution for xy^'=y^2+3 ?

The solution for xy^'=y^2+3 is y=tan(sqrt(3)(ln(x)+c_{1}))sqrt(3)

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xy^'=y^2+3

x y^{^{'}} = y^{2} + 3

y = tan (3 (ln (x) + c_{1})) 3

Solution steps

x y^{'} (x) = y^{2} + 3

Solve separable ODE:

y = tan (3 (ln (x) + c_{1})) 3

y = tan (3 (ln (x) + c_{1})) 3

2 x y^{^{'}} = 4 - y^{2}

\frac{d y}{d x} + 7 x y = 8 x

y^{^{'}} = e^{2 y - x}

\frac{d P}{d t} = 0.02 P (1 - \frac{P}{250000})

y^{^{'}} = - 0.00003 (y - 288.03) (y - 961.97)

What is the solution for xy^'=y^2+3 ?
The solution for xy^'=y^2+3 is y=tan(sqrt(3)(ln(x)+c_{1}))sqrt(3)