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Popular >

y^'=e^{2y-x}

Solution

y^{^{'}} = e^{2 y - x}

Solution

y = - \frac{ln ( 2 e ^{- x} - c _{1} )}{2}

Solution steps

y^{'} (x) = e^{2 y - x}

Solve separable ODE:

y = - \frac{ln ( 2 e ^{- x} - c _{1} )}{2}

y = - \frac{ln ( 2 e ^{- x} - c _{1} )}{2}

Graph

Popular Examples

(dP)/(dt)=0.02P(1-P/(250000))

\frac{d P}{d t} = 0.02 P (1 - \frac{P}{250000})

y^'=-0.00003(y-288.03)(y-961.97)

y^{^{'}} = - 0.00003 (y - 288.03) (y - 961.97)

(dy)/(dx)=4x(y^2+1)

\frac{d y}{d x} = 4 x (y^{2} + 1)

\frac{d y}{d t} = 4 - y

y^{^{'}} = x + x y

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{2y-x} ?
The solution for y^'=e^{2y-x} is y=-(ln(2e^{-x}-c_{1}))/2