What is the solution for (dy)/(dx)=-3/4 x^4y^2 ?

The solution for (dy)/(dx)=-3/4 x^4y^2 is y=-(20)/(-3x^5+c_{1)}

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(dy)/(dx)=-3/4 x^4y^2

\frac{d y}{d x} = - \frac{3}{4} x^{4} y^{2}

y = - \frac{20}{- 3 x ^{5} + c _{1}}

Solution steps

\frac{d y}{d x} = - \frac{3}{4} x^{4} y^{2}

Solve separable ODE:

y = - \frac{20}{- 3 x ^{5} + c _{1}}

y = - \frac{20}{- 3 x ^{5} + c _{1}}

y^{^{'}} = 12 x y - 2 x, y (0) = 17

\frac{d y}{d t} + 2 y = 3, y (0) = 1

\frac{d y}{d x} + y cos (x) = 6 cos (x)

e^{x} d x - (1 + e^{x}) y d y = 0

\frac{x ^{2}}{y ^{2} - 3} \frac{d y}{d x} = \frac{1}{2 y}

What is the solution for (dy)/(dx)=-3/4 x^4y^2 ?
The solution for (dy)/(dx)=-3/4 x^4y^2 is y=-(20)/(-3x^5+c_{1)}