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Popular >

(dy)/(dt)=e^{(t+y)}

Solution

\frac{d y}{d t} = e^{(t + y)}

Solution

y = - ln (- e^{t} - c_{1})

Solution steps

\frac{d y}{d t} = e^{(t + y)}

Solve separable ODE:

y = - ln (- e^{t} - c_{1})

y = - ln (- e^{t} - c_{1})

Popular Examples

(dy)/(dx)=(2ln(x))/(xy)

\frac{d y}{d x} = \frac{2 ln ( x )}{x y}

(dy)/(dx)+x^4y=4x^4

\frac{d y}{d x} + x^{4} y = 4 x^{4}

x^'=(x^2+x)/(2x+1),x(0)=1

x^{^{'}} = \frac{x ^{2} + x}{2 x + 1}, x (0) = 1

sec^2(x)dx+sqrt(1-y)dy=0

sec^{2} (x) d x + 1 - y d y = 0

y-xy^'=1992(1+x^2y^')

y - x y^{^{'}} = 1992 (1 + x^{2} y^{^{'}})

Frequently Asked Questions (FAQ)

What is the solution for (dy)/(dt)=e^{(t+y)} ?
The solution for (dy)/(dt)=e^{(t+y)} is y=-ln(-e^t-c_{1})