What is the solution for (dy)/(dx)+4y=20,y(0)=2 ?

The solution for (dy)/(dx)+4y=20,y(0)=2 is y=-3e^{-4x}+5

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(dy)/(dx)+4y=20,y(0)=2

\frac{d y}{d x} + 4 y = 20, y (0) = 2

y = - 3 e^{- 4 x} + 5

Solution steps

\frac{d y}{d x} + 4 y = 20

Solve separable ODE:

y = - 3 e^{- 4 x} + 5

y = - 3 e^{- 4 x} + 5

y^{^{'}} = \frac{x y + x + y + 1}{x y + 2 x - y - 2}

y^{^{'}} = sin (2 x) y^{2}

y^{^{'}} = \frac{y ^{2}}{x ^{3}}

y tan (x) d x + cos^{2} (x) d y = 0

\frac{d y}{d x} = \frac{1}{2} y cos^{2} (y)

What is the solution for (dy)/(dx)+4y=20,y(0)=2 ?
The solution for (dy)/(dx)+4y=20,y(0)=2 is y=-3e^{-4x}+5