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Popular >

y^'=sin(2x)y^2

Solution

y^{^{'}} = sin (2 x) y^{2}

Solution

y = - \frac{2}{- cos ( 2 x ) + c _{1}}

Solution steps

y^{'} (x) = sin (2 x) y^{2}

Solve separable ODE:

y = - \frac{2}{- cos ( 2 x ) + c _{1}}

y = - \frac{2}{- cos ( 2 x ) + c _{1}}

Popular Examples

y^'=(y^2)/(x^3)

y^{^{'}} = \frac{y ^{2}}{x ^{3}}

ytan(x)dx+cos^2(x)dy=0

y tan (x) d x + cos^{2} (x) d y = 0

(dy)/(dx)= 1/2 sqrt(y)cos^2(sqrt(y))

\frac{d y}{d x} = \frac{1}{2} y cos^{2} (y)

x y^{^{'}} - y = y^{2}

y^'=((x-2)^2)/y ,y(0)=1

y^{^{'}} = \frac{( x - 2 ) ^{2}}{y}, y (0) = 1

Frequently Asked Questions (FAQ)

What is the solution for y^'=sin(2x)y^2 ?
The solution for y^'=sin(2x)y^2 is y=-2/(-cos(2x)+c_{1)}