en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f^'(x)=-2x+8

Solution

f^{^{'}} (x) = - 2 x + 8

Solution

f (x) = - x^{2} + 8 x + c_{1}

Solution steps

f^{'} (x) = - 2 x + 8

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int - 2 x + 8 d x

\int - 2 x + 8 d x = - x^{2} + 8 x + c_{1}

f (x) = - x^{2} + 8 x + c_{1}

Popular Examples

x y^{^{''}} - y^{^{'}} = 0

integral of (4x^2-3x)^4(8x-3)

\int (4 x^{2} - 3 x)^{4} (8 x - 3) d x

d/(dt)(t+sin(t))

\frac{d}{d t} (t + sin (t))

integral of 1/5 e^{5x}

\int \frac{1}{5} e^{5 x} d x

sum from n=1 to infinity of 4(3/2)^{n-1}

n = 1 \sum \infty 4 (\frac{3}{2})^{n - 1}

Frequently Asked Questions (FAQ)

What is the solution for f^'(x)=-2x+8 ?
The solution for f^'(x)=-2x+8 is f(x)=-x^2+8x+c_{1}