What is the integral of 1/5 e^{5x} ?

The integral of 1/5 e^{5x} is 1/25 e^{5x}+C

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integral of 1/5 e^{5x}

\int \frac{1}{5} e^{5 x} d x

\frac{1}{25} e^{5 x} + C

Solution steps

\int \frac{1}{5} e^{5 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int e^{5 x} d x

Apply u-substitution

: \int e^{u} \frac{1}{5} d u

= \frac{1}{5} \cdot \int e^{u} \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \frac{1}{5} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{5} \cdot \frac{1}{5} e^{u}

Substitute back

u = 5 x

= \frac{1}{5} \cdot \frac{1}{5} e^{5 x}

Simplify

\frac{1}{5} \cdot \frac{1}{5} e^{5 x} : \frac{1}{25} e^{5 x}

= \frac{1}{25} e^{5 x}

Add a constant to the solution

= \frac{1}{25} e^{5 x} + C

n = 1 \sum \infty 4 (\frac{3}{2})^{n - 1}

\frac{d y}{d x} = \frac{y ( x - y )}{x ^{2}}

\frac{d}{d x} (sin (x) \cdot cos (x) \cdot \frac{1}{x})

y = 6 x^{2}, y = 4 x^{2}, y = 6 - 5 x

\frac{d}{d x} (2 cos (x) + 2)

What is the integral of 1/5 e^{5x} ?
The integral of 1/5 e^{5x} is 1/25 e^{5x}+C