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Popular >

y^'+(x+7)y=0

Solution

y^{^{'}} + (x + 7) y = 0

Solution

y = e^{- \frac{x ^{2}}{2} - 7 x + c_{1}}

Solution steps

y^{'} (x) + (x + 7) y = 0

Solve separable ODE:

y = e^{- \frac{x ^{2}}{2} - 7 x + c_{1}}

y = e^{- \frac{x ^{2}}{2} - 7 x + c_{1}}

Popular Examples

(dy)/(dx)=(x+3x^2)/(y^2)

\frac{d y}{d x} = \frac{x + 3 x ^{2}}{y ^{2}}

ydx+(1+x^2)arctan(x)dy=0

y d x + (1 + x^{2}) arctan (x) d y = 0

y^'cos(x)+(3y-1)sec(x)=0,y(1/4 pi)= 4/3

y^{^{'}} cos (x) + (3 y - 1) sec (x) = 0, y (\frac{1}{4} π) = \frac{4}{3}

x^'=(1+x)/(1+t)

x^{^{'}} = \frac{1 + x}{1 + t}

y^'+2xy^2=0,y(0)=1

y^{^{'}} + 2 x y^{2} = 0, y (0) = 1

Frequently Asked Questions (FAQ)

What is the solution for y^'+(x+7)y=0 ?
The solution for y^'+(x+7)y=0 is y=e^{-(x^2)/2-7x+c_{1}}