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Popular >

f^'(x)=2f(x)

Solution

f^{^{'}} (x) = 2 f (x)

Solution

f (x) = e^{2 x + c_{1}}

Solution steps

f^{'} (x) = 2 f (x)

Solve separable ODE:

f (x) = e^{2 x + c_{1}}

f (x) = e^{2 x + c_{1}}

Popular Examples

(x^2+1)(dy)/(dx)=x(y+1)

(x^{2} + 1) \frac{d y}{d x} = x (y + 1)

y^'=(((x-2)^2))/y ,y(0)=1

y^{^{'}} = \frac{( ( x - 2 ) ^{2} )}{y}, y (0) = 1

(dy)/(dx)=-3/7 x^6y^4

\frac{d y}{d x} = - \frac{3}{7} x^{6} y^{4}

(dy}{dx}=\frac{sqrt(y)ln(x))/x ,y(1)=0

\frac{d y}{d x} = \frac{y ln ( x )}{x}, y (1) = 0

(1 - x) y^{^{'}} - y = 0

Frequently Asked Questions (FAQ)

What is the solution for f^'(x)=2f(x) ?
The solution for f^'(x)=2f(x) is f(x)=e^{2x+c_{1}}