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Popular >

(xy^2+y^2)dx+xdy=0

Solution

(x y^{2} + y^{2}) d x + x d y = 0

Solution

y = - \frac{1}{- x - ln ( x ) + c _{1}}

Solution steps

(x y^{2} + y^{2}) d x + x d y = 0

Solve separable ODE:

y = - \frac{1}{- x - ln ( x ) + c _{1}}

y = - \frac{1}{- x - ln ( x ) + c _{1}}

Popular Examples

(dy)/(dx)+3e^{x+y}=0

\frac{d y}{d x} + 3 e^{x + y} = 0

y^'=sin(x)cos^2(x)tan(y)

y^{^{'}} = sin (x) cos^{2} (x) tan (y)

(dy)/(dx)=(xy)/(x^2)

\frac{d y}{d x} = \frac{x y}{x ^{2}}

(dy)/(dx)=y^2sin(x),y(0)=3

\frac{d y}{d x} = y^{2} sin (x), y (0) = 3

(dy)/(dx)+xy=xy^{-1/2}

\frac{d y}{d x} + x y = x y^{- \frac{1}{2}}

Frequently Asked Questions (FAQ)

What is the solution for (xy^2+y^2)dx+xdy=0 ?
The solution for (xy^2+y^2)dx+xdy=0 is y=-1/(-x-ln(x)+c_{1)}