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Popular >

(dq)/(dt)=kq(t)^2

Solution

\frac{d q}{d t} = k q (t)^{2}

Solution

q = e^{\frac{k t ^{3}}{3} + c_{1}}

Solution steps

\frac{d q}{d t} = k q t^{2}

Solve separable ODE:

q = e^{\frac{k t ^{3}}{3} + c_{1}}

q = e^{\frac{k t ^{3}}{3} + c_{1}}

Popular Examples

y^'=(e^{-x})/(sin(y)),y(1)=0

y^{^{'}} = \frac{e ^{- x}}{sin ( y )}, y (1) = 0

y^{^{'}} + 12 x y = 0

(dy)/(dx)=3y+y^2-2

\frac{d y}{d x} = 3 y + y^{2} - 2

y^{^{'}} + (x + 8) y = 0

sec^2(x)tan(y)dx+sec^2(y)tan(x)dy=0

sec^{2} (x) tan (y) d x + sec^{2} (y) tan (x) d y = 0

Frequently Asked Questions (FAQ)

What is the solution for (dq)/(dt)=kq(t)^2 ?
The solution for (dq)/(dt)=kq(t)^2 is q=e^{(kt^3)/3+c_{1}}