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Popular >

y^'+12xy=0

Solution

y^{^{'}} + 12 x y = 0

Solution

y = e^{- 6 x^{2} + c_{1}}

Solution steps

y^{'} (x) + 12 x y = 0

Solve separable ODE:

y = e^{- 6 x^{2} + c_{1}}

y = e^{- 6 x^{2} + c_{1}}

Popular Examples

(dy)/(dx)=3y+y^2-2

\frac{d y}{d x} = 3 y + y^{2} - 2

y^{^{'}} + (x + 8) y = 0

sec^2(x)tan(y)dx+sec^2(y)tan(x)dy=0

sec^{2} (x) tan (y) d x + sec^{2} (y) tan (x) d y = 0

\frac{y}{x} y^{^{'}} + e^{y} = 0

(t^2-22t+96)(dy)/(dt)=y

(t^{2} - 22 t + 96) \frac{d y}{d t} = y

Frequently Asked Questions (FAQ)

What is the solution for y^'+12xy=0 ?
The solution for y^'+12xy=0 is y=e^{-6x^2+c_{1}}