What is the solution for y^'+ycos(x)=3cos(x) ?

The solution for y^'+ycos(x)=3cos(x) is y=e^{-sin(x)+c_{1}}+3

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y^'+ycos(x)=3cos(x)

y^{^{'}} + y cos (x) = 3 cos (x)

y = e^{- s i n (x) + c_{1}} + 3

Solution steps

y^{'} (x) + y cos (x) = 3 cos (x)

Solve separable ODE:

y = e^{- s i n (x) + c_{1}} + 3

y = e^{- s i n (x) + c_{1}} + 3

\frac{d y}{d x} + \frac{e ^{y^{2}}}{x ^{2} y} = 0, y (1) = 0

x \frac{d y}{d x} = y x - x y cos (x)

\frac{d x}{d t} - x^{3} = x

y^{^{'}} + 20 x y = 0

(2 y + y x^{2}) d y = (x + x y^{2}) d x

What is the solution for y^'+ycos(x)=3cos(x) ?
The solution for y^'+ycos(x)=3cos(x) is y=e^{-sin(x)+c_{1}}+3