What is the solution for x^'=e^xtcos(t) ?

The solution for x^'=e^xtcos(t) is x=-ln(-tsin(t)-cos(t)-c_{1})

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x^'=e^xtcos(t)

x^{^{'}} = e^{x} t cos (t)

x = - ln (- t sin (t) - cos (t) - c_{1})

Solution steps

x^{'} (t) = e^{x} t cos (t)

Solve separable ODE:

x = - ln (- t sin (t) - cos (t) - c_{1})

x = - ln (- t sin (t) - cos (t) - c_{1})

\frac{d y}{d x} = 8 x y^{2}

\frac{d x}{d t} + cos (t) x = cos (t)

5 x y \frac{d y}{d x} = 4, y > 0

\frac{d v}{d t} = \frac{2}{9} v

\frac{d y}{d x} = 4 cos (x) sec (y)

What is the solution for x^'=e^xtcos(t) ?
The solution for x^'=e^xtcos(t) is x=-ln(-tsin(t)-cos(t)-c_{1})