What is the solution for y^'=-(sin(x))(cos^2(y)) ?

The solution for y^'=-(sin(x))(cos^2(y)) is y=arctan(cos(x)+c_{1})+pin

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y^'=-(sin(x))(cos^2(y))

y^{^{'}} = - (sin (x)) (cos^{2} (y))

y = arctan (cos (x) + c_{1}) + πn

Solution steps

y^{'} (x) = - (sin (x)) (cos^{2} (y))

Solve separable ODE:

y = arctan (cos (x) + c_{1}) + πn

y = arctan (cos (x) + c_{1}) + πn

y^{^{'}} = - \frac{9 x}{y}

6 (y^{2} + 2 x y \frac{d y}{d x}) + 18 x = - 4 y^{3} \frac{d y}{d x}

y^{^{'}} (x) = \frac{y}{x ( y - 3 )}, y (2) = 6

\frac{d}{d x} (x^{2} sec (y)) = 8 x

\frac{d x}{d t} + \frac{9}{50} x = 15

What is the solution for y^'=-(sin(x))(cos^2(y)) ?
The solution for y^'=-(sin(x))(cos^2(y)) is y=arctan(cos(x)+c_{1})+pin