What is the solution for (dx)/(dt)+9/50 x=15 ?

The solution for (dx)/(dt)+9/50 x=15 is x=-(e^{(-9t-c_{1})/(50)})/9+250/3

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(dx)/(dt)+9/50 x=15

\frac{d x}{d t} + \frac{9}{50} x = 15

x = - \frac{e ^{\frac{- 9 t - c _{1}}{50}}}{9} + \frac{250}{3}

Solution steps

\frac{d x}{d t} + \frac{9}{50} x = 15

Solve separable ODE:

x = - \frac{e ^{\frac{- 9 t - c _{1}}{50}}}{9} + \frac{250}{3}

x = - \frac{e ^{\frac{- 9 t - c _{1}}{50}}}{9} + \frac{250}{3}

y^{5} \frac{d y}{d x} = 5 x^{2} y^{6} - 15 x^{2}

y^{^{'}} cos (y) + 2 x sin (y) = 2 x

\frac{d y}{d x} = cos (x) - y \cdot cos (x)

y^{^{'}} - a^{2} y = 0

\frac{d y}{d x} = \frac{x}{y + x ^{2} y}

What is the solution for (dx)/(dt)+9/50 x=15 ?
The solution for (dx)/(dt)+9/50 x=15 is x=-(e^{(-9t-c_{1})/(50)})/9+250/3