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Popular >

y^'=x(10-y)

Solution

y^{^{'}} = x (10 - y)

Solution

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 10

Solution steps

y^{'} (x) = x (10 - y)

Solve separable ODE:

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 10

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 10

Popular Examples

(dy)/(dx)=-5/7 x^3y^2

\frac{d y}{d x} = - \frac{5}{7} x^{3} y^{2}

sqrt(y)(dy)/(dx)+sqrt(y^3)=1,y(4)=0

y \frac{d y}{d x} + y^{3} = 1, y (4) = 0

(x^{2} + 25) y^{^{'}} = x y

x^2(dy)/(dx)+1/x y= 2/x y^{-3}

x^{2} \frac{d y}{d x} + \frac{1}{x} y = \frac{2}{x} y^{- 3}

(dx)/(dy)=1-0.4x

\frac{d x}{d y} = 1 - 0.4 x

Frequently Asked Questions (FAQ)

What is the solution for y^'=x(10-y) ?
The solution for y^'=x(10-y) is y=-e^{-(x^2)/2-c_{1}}+10