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Popular >

y+xy^'=0

Solution

y + x y^{^{'}} = 0

Solution

y = \frac{c _{1}}{x}

Solution steps

y + x y^{'} (x) = 0

Solve separable ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

Popular Examples

6 y^{^{'}} - 2 y = y^{4}

y(225-x^2)^{1/2}dy=(225+y^2)^{1/2}dx

y (225 - x^{2})^{\frac{1}{2}} d y = (225 + y^{2})^{\frac{1}{2}} d x

x^{^{'}} = 1 + x^{2}

y^'+(cos(x))y=cos(x)

y^{^{'}} + (cos (x)) y = cos (x)

(x^2+1)(tan(y))(dy)/(dx)=x

(x^{2} + 1) (tan (y)) \frac{d y}{d x} = x

Frequently Asked Questions (FAQ)

What is the solution for y+xy^'=0 ?
The solution for y+xy^'=0 is y=(c_{1})/x