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Popular >

(dy)/(dx)+5xe^y=0

Solution

\frac{d y}{d x} + 5 x e^{y} = 0

Solution

y = - ln (\frac{5 x ^{2}}{2} - c_{1})

Solution steps

\frac{d y}{d x} + 5 x e^{y} = 0

Solve separable ODE:

y = - ln (\frac{5 x ^{2}}{2} - c_{1})

y = - ln (\frac{5 x ^{2}}{2} - c_{1})

Popular Examples

e^{y} y^{^{'}} - x^{2} = 0

y(169-x^2)^{1/2}dy=(169+y^2)^{1/2}dx

y (169 - x^{2})^{\frac{1}{2}} d y = (169 + y^{2})^{\frac{1}{2}} d x

(dx)/(dt)=-2x+1

\frac{d x}{d t} = - 2 x + 1

2y^'+y=0,y(0)=e-x/2

2 y^{^{'}} + y = 0, y (0) = e - \frac{x}{2}

(dy)/(dx)=(x^2-xy-x+y)/(xy-y^2)

\frac{d y}{d x} = \frac{x ^{2} - x y - x + y}{x y - y ^{2}}

Frequently Asked Questions (FAQ)

What is the solution for (dy)/(dx)+5xe^y=0 ?
The solution for (dy)/(dx)+5xe^y=0 is y=-ln((5x^2)/2-c_{1})