What is the solution for (dy)/(dx)=2xy^2,y=-1,x=1 ?

The solution for (dy)/(dx)=2xy^2,y=-1,x=1 is y=-1/(x^2)

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(dy)/(dx)=2xy^2,y=-1,x=1

\frac{d y}{d x} = 2 x y^{2}, y = - 1, x = 1

y = - \frac{1}{x ^{2}}

Solution steps

\frac{d y}{d x} = 2 x y^{2}

Solve separable ODE:

y = - \frac{1}{x ^{2}}

y = - \frac{1}{x ^{2}}

y^{^{'}} = 5 e^{x - y}

y (4 - x^{2})^{\frac{1}{2}} d y = (4 + y^{2})^{\frac{1}{2}} d x

x y^{^{'}} = y tan (ln (y))

\frac{d y}{d t} = - \frac{t}{2 y}

(3 x y^{2} - x^{3}) \frac{d y}{d x} = 3 y^{3} - x^{2} y

What is the solution for (dy)/(dx)=2xy^2,y=-1,x=1 ?
The solution for (dy)/(dx)=2xy^2,y=-1,x=1 is y=-1/(x^2)