What is the solution for (dy)/(dx)=(y^2+y^2cos(x))^2 ?

The solution for (dy)/(dx)=(y^2+y^2cos(x))^2 is y=-\sqrt[3]{4/(3(6x+sin(2x)+8sin(x)+c_{1))}}

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(dy)/(dx)=(y^2+y^2cos(x))^2

\frac{d y}{d x} = (y^{2} + y^{2} cos (x))^{2}

Solution steps

\frac{d y}{d x} = (y^{2} + y^{2} cos (x))^{2}

Solve separable ODE:

y^{^{'}} = - 3 y^{\frac{4}{3}} sin (t)

\frac{d y}{d x} = \frac{x + 1}{e ^{y}}

\frac{d y}{d x} = - \frac{8}{9} x^{2} y^{6}

y^{^{'}} = (\frac{2}{x} - x) y

x^{5} \frac{d y}{d x} = 3 x^{2} 1 - y^{2}

What is the solution for (dy)/(dx)=(y^2+y^2cos(x))^2 ?
The solution for (dy)/(dx)=(y^2+y^2cos(x))^2 is y=-\sqrt[3]{4/(3(6x+sin(2x)+8sin(x)+c_{1))}}