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Popular >

4xy^'-2xy=7x

Solution

4 x y^{^{'}} - 2 x y = 7 x

Solution

y = \frac{e ^{\frac{x + c _{1}}{2}}}{2} - \frac{7}{2}

Solution steps

4 x y^{'} (x) - 2 x y = 7 x

Solve separable ODE:

y = \frac{e ^{\frac{x + c _{1}}{2}}}{2} - \frac{7}{2}

y = \frac{e ^{\frac{x + c _{1}}{2}}}{2} - \frac{7}{2}

Popular Examples

y^{^{'}} + r x y = 0

(((x+1)^2+6)/(4(x+1)))((dy)/(dx))=tan(y)

(\frac{( x + 1 ) ^{2} + 6}{4 ( x + 1 )}) (\frac{d y}{d x}) = tan (y)

(dy}{dx}=-\frac{ay)/x

\frac{d y}{d x} = - \frac{a y}{x}

y*y^'-2x=sin(x)

y \cdot y^{^{'}} - 2 x = sin (x)

(dy)/(dx)=0.125(y-3),y(0)=5

\frac{d y}{d x} = 0.125 (y - 3), y (0) = 5

Frequently Asked Questions (FAQ)

What is the solution for 4xy^'-2xy=7x ?
The solution for 4xy^'-2xy=7x is y=(e^{(x+c_{1})/2})/(2)-7/2