What is the sum from n=1 to infinity of arctan(6n) ?

The sum from n=1 to infinity of arctan(6n) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of arctan(6n)

n = 1 \sum \infty arctan (6 n)

diverges

Solution steps

n = 1 \sum \infty arctan (6 n)

Apply Series Divergence Test:

diverges

= diverges

\int x^{2} x d x

\frac{d}{d t} (e^{(7 t s i n (2 t))})

e^{, at}

y^{^{'}} = 2 y - t

f (x) = \frac{ln ( x )}{x ^{9}}

What is the sum from n=1 to infinity of arctan(6n) ?
The sum from n=1 to infinity of arctan(6n) is diverges