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Popular >

y^'=(-2xy)/(x^2+1)

Solution

y^{^{'}} = \frac{- 2 x y}{x ^{2} + 1}

Solution

y = \frac{c _{1}}{x ^{2} + 1}

Solution steps

y^{'} (x) = \frac{- 2 x y}{x ^{2} + 1}

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} + 1}

y = \frac{c _{1}}{x ^{2} + 1}

Popular Examples

y^{^{'}} = \frac{x}{y - 1}

(dy)/(dx)=y(2x^2+1)

\frac{d y}{d x} = y (2 x^{2} + 1)

(dy)/(dx)=((x^2-1)/(y^2))

\frac{d y}{d x} = (\frac{x ^{2} - 1}{y ^{2}})

(dy)/(dx)=y(2x^2+4)

\frac{d y}{d x} = y (2 x^{2} + 4)

(3x^2y+2y)dx+(x^3+2x)dy=0

(3 x^{2} y + 2 y) d x + (x^{3} + 2 x) d y = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=(-2xy)/(x^2+1) ?
The solution for y^'=(-2xy)/(x^2+1) is y=(c_{1})/(x^2+1)