What is the solution for (dy)/(dx)=((x^2-1)/(y^2)) ?

The solution for (dy)/(dx)=((x^2-1)/(y^2)) is y=\sqrt[3]{x^3-3x+c_{1}}

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(dy)/(dx)=((x^2-1)/(y^2))

\frac{d y}{d x} = (\frac{x ^{2} - 1}{y ^{2}})

Solution steps

\frac{d y}{d x} = (\frac{x ^{2} - 1}{y ^{2}})

Solve separable ODE:

\frac{d y}{d x} = y (2 x^{2} + 4)

(3 x^{2} y + 2 y) d x + (x^{3} + 2 x) d y = 0

y^{^{'}} = \frac{x - 1}{y ^{2}}

\frac{d y}{d x} = \frac{( 3 e ^{x} )}{( 3 y + 1 )}

\frac{d y}{d x} = \frac{1}{y + x ^{2} y}

What is the solution for (dy)/(dx)=((x^2-1)/(y^2)) ?
The solution for (dy)/(dx)=((x^2-1)/(y^2)) is y=\sqrt[3]{x^3-3x+c_{1}}