What is the solution for (dv)/(dt)=g-kv(t),v=0,t=0 ?

The solution for (dv)/(dt)=g-kv(t),v=0,t=0 is v=-(ge^{-kt})/k+g/k

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(dv)/(dt)=g-kv(t),v=0,t=0

\frac{d v}{d t} = g - k v (t), v = 0, t = 0

v = - \frac{g e ^{- k t}}{k} + \frac{g}{k}

Solution steps

\frac{d v}{d t} = g - k v

Solve separable ODE:

v = - \frac{g e ^{- k t}}{k} + \frac{g}{k}

v = - \frac{g e ^{- k t}}{k} + \frac{g}{k}

\frac{d y}{d x} + 2 y = 11

\frac{d y}{d x} y = e^{x^{2 l n (x)}}

x^{^{'}} = (x)^{45 + 2} (ln (t) + (2 + 2) t e^{t})

y^{^{'}} = x^{3} y

x^{2} \frac{d y}{d x} = y (3 x + 2)

What is the solution for (dv)/(dt)=g-kv(t),v=0,t=0 ?
The solution for (dv)/(dt)=g-kv(t),v=0,t=0 is v=-(ge^{-kt})/k+g/k