What is the solution for (x^2+3x)(dy)/(dx)+3y=-3xy ?

The solution for (x^2+3x)(dy)/(dx)+3y=-3xy is y=(c_{1})/(x^3+6x^2+9x)

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(x^2+3x)(dy)/(dx)+3y=-3xy

(x^{2} + 3 x) \frac{d y}{d x} + 3 y = - 3 x y

y = \frac{c _{1}}{x ^{3} + 6 x ^{2} + 9 x}

Solution steps

(x^{2} + 3 x) \frac{d y}{d x} + 3 y = - 3 x y

Solve separable ODE:

y = \frac{c _{1}}{x ^{3} + 6 x ^{2} + 9 x}

y = \frac{c _{1}}{x ^{3} + 6 x ^{2} + 9 x}

y^{^{'}} = 5 y e^{t}, y (0) = 1

x^{2} y^{^{'}} = x y^{2}

\frac{x}{100} + \frac{d x}{d t} = 1

\frac{d}{d x} (x^{2}) + \frac{d}{d x} (y^{2}) = 0

y^{^{'}} = \frac{4 y ^{2}}{x}

What is the solution for (x^2+3x)(dy)/(dx)+3y=-3xy ?
The solution for (x^2+3x)(dy)/(dx)+3y=-3xy is y=(c_{1})/(x^3+6x^2+9x)