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Popular >

x^2y^'=xy^2

Solution

x^{2} y^{^{'}} = x y^{2}

Solution

y = - \frac{1}{ln ( x ) + c _{1}}

Solution steps

x^{2} y^{'} (x) = x y^{2}

Solve separable ODE:

y = - \frac{1}{ln ( x ) + c _{1}}

y = - \frac{1}{ln ( x ) + c _{1}}

Popular Examples

x/(100)+(dx)/(dt)=1

\frac{x}{100} + \frac{d x}{d t} = 1

derivative of x^2+derivative of y^2=0

\frac{d}{d x} (x^{2}) + \frac{d}{d x} (y^{2}) = 0

y^'=(4y^2)/(sqrt(x))

y^{^{'}} = \frac{4 y ^{2}}{x}

x^{^{'}} = - 5 x + 4 x

y*y^'-x*y^2+x=0

y \cdot y^{^{'}} - x \cdot y^{2} + x = 0

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'=xy^2 ?
The solution for x^2y^'=xy^2 is y=-1/(ln(x)+c_{1)}