What is the solution for y*y^'-x*y^2+x=0 ?

The solution for y*y^'-x*y^2+x=0 is y=sqrt(e^{x^2+c_{1)}+1},y=-sqrt(e^{x^2+c_{1)}+1}

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yy^'-xy^2+x=0

y \cdot y^{^{'}} - x \cdot y^{2} + x = 0

y = e^{x^{2} + c_{1}} + 1, y = - e^{x^{2} + c_{1}} + 1

Solution steps

y \cdot y^{'} (x) - x \cdot y^{2} + x = 0

Solve separable ODE:

y = e^{x^{2} + c_{1}} + 1, y = - e^{x^{2} + c_{1}} + 1

y = e^{x^{2} + c_{1}} + 1, y = - e^{x^{2} + c_{1}} + 1

cos (2 y) d y = d x

y d x + (x - 1) d y = 0, y (2) = 25

2 y y^{^{'}} = 18 t^{2}, y (0) = 7

\frac{d y}{d t} + 2 y = 5, y (0) = 1

\frac{d y}{d x} = \frac{3 x + x y ^{2}}{2 y + x ^{2} y}, y (2) = 1

What is the solution for y*y^'-x*y^2+x=0 ?
The solution for y*y^'-x*y^2+x=0 is y=sqrt(e^{x^2+c_{1)}+1},y=-sqrt(e^{x^2+c_{1)}+1}