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Popular >

2yy^'=18t^2,y(0)=7

Solution

2 y y^{^{'}} = 18 t^{2}, y (0) = 7

Solution

y = 6 t^{3} + 49

Solution steps

2 y y^{'} (t) = 18 t^{2}

Solve separable ODE:

y = 6 t^{3} + 49

y = 6 t^{3} + 49

Popular Examples

(dy)/(dt)+2y=5,y(0)=1

\frac{d y}{d t} + 2 y = 5, y (0) = 1

(dy)/(dx)=(3x+xy^2)/(2y+x^2y),y(2)=1

\frac{d y}{d x} = \frac{3 x + x y ^{2}}{2 y + x ^{2} y}, y (2) = 1

\frac{d y}{d x} = 800 y

sqrt(1-x^2)dy-xydx=0,y(1)=2

1 - x^{2} d y - x y d x = 0, y (1) = 2

(dy)/(dx)+y=2,y(0)=0

\frac{d y}{d x} + y = 2, y (0) = 0

Frequently Asked Questions (FAQ)

What is the solution for 2yy^'=18t^2,y(0)=7 ?
The solution for 2yy^'=18t^2,y(0)=7 is y=sqrt(6t^3+49)