What is the solution for (dy)/(dx)=y(4x^2+4) ?

The solution for (dy)/(dx)=y(4x^2+4) is y=e^{(4x^3)/3+4x+c_{1}}

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(dy)/(dx)=y(4x^2+4)

\frac{d y}{d x} = y (4 x^{2} + 4)

y = e^{\frac{4 x ^{3}}{3} + 4 x + c_{1}}

Solution steps

\frac{d y}{d x} = y (4 x^{2} + 4)

Solve separable ODE:

y = e^{\frac{4 x ^{3}}{3} + 4 x + c_{1}}

y = e^{\frac{4 x ^{3}}{3} + 4 x + c_{1}}

d x = x^{6} y d y

y y^{^{'}} = x - y x

(y ln (x)) y^{^{'}} = \frac{y ^{2} + 1}{x}

\frac{d y}{d x} = \frac{x sin ( x )}{y}, y (0) = - 7

\frac{d y}{d x} = \frac{x sin ( x )}{y}, y (0) = - 9

What is the solution for (dy)/(dx)=y(4x^2+4) ?
The solution for (dy)/(dx)=y(4x^2+4) is y=e^{(4x^3)/3+4x+c_{1}}