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Popular >

yy^'=x-yx

Solution

y y^{^{'}} = x - y x

Solution

y = W (\frac{1}{e ^{\frac{- c _{1} + x ^{2}}{2}}}) + 1

Solution steps

y y^{'} (x) = x - y x

Solve separable ODE:

y = W (\frac{1}{e ^{\frac{- c _{1} + x ^{2}}{2}}}) + 1

y = W (\frac{1}{e ^{\frac{- c _{1} + x ^{2}}{2}}}) + 1

Popular Examples

(yln(x))y^'=(y^2+1)/x

(y ln (x)) y^{^{'}} = \frac{y ^{2} + 1}{x}

(dy}{dx}=\frac{xsin(x))/y ,y(0)=-7

\frac{d y}{d x} = \frac{x sin ( x )}{y}, y (0) = - 7

(dy}{dx}=\frac{xsin(x))/y ,y(0)=-9

\frac{d y}{d x} = \frac{x sin ( x )}{y}, y (0) = - 9

y^{^{'}} = 2 - 0.1 y

(dx)/(dt)=x^2+1/25 ,x(0)=-3

\frac{d x}{d t} = x^{2} + \frac{1}{25}, x (0) = - 3

Frequently Asked Questions (FAQ)

What is the solution for yy^'=x-yx ?
The solution for yy^'=x-yx is y=\W(1/(e^{(-c_{1)+x^2)/2}})+1