What is the tangent of y=3e^xcos(x),(0,3) ?

The tangent of y=3e^xcos(x),(0,3) is y=3x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=3e^xcos(x),(0,3)

tangent of

y = 3 e^{x} cos (x), (0, 3)

y = 3 x + 3

Solution steps

Find the slope of

y = 3 e^{x} cos (x) : \frac{d y}{d x} = 3 (e^{x} cos (x) - e^{x} sin (x))

Compute the slope of

y = 3 e^{x} cos (x)

(0, 3) : m = 3

Find the line with slope m=

3

and passing through

(0, 3) : y = 3 x + 3

y = 3 x + 3

4 y^{^{''}} + 12 y^{^{'}} + 9 y = 0

y^{^{'}} = \frac{y}{x} + 2 x + 1

f (x) = \frac{1}{2} x^{8}

\frac{\partial}{\partial x} (y e^{x} + x e^{y})

t

What is the tangent of y=3e^xcos(x),(0,3) ?
The tangent of y=3e^xcos(x),(0,3) is y=3x+3