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Popular >

y^'=3xy+5y

Solution

y^{^{'}} = 3 x y + 5 y

Solution

y = e^{\frac{3 x ^{2}}{2} + 5 x + c_{1}}

Solution steps

y^{'} (x) = 3 x y + 5 y

Solve separable ODE:

y = e^{\frac{3 x ^{2}}{2} + 5 x + c_{1}}

y = e^{\frac{3 x ^{2}}{2} + 5 x + c_{1}}

Popular Examples

y^'=(cos^2(x))/(y^2)

y^{^{'}} = \frac{cos ^{2} ( x )}{y ^{2}}

y^2y^'=x^2+6e^x

y^{2} y^{^{'}} = x^{2} + 6 e^{x}

(dy)/(dx)=((3x^2+4x+2))/(2(y-1))

\frac{d y}{d x} = \frac{( 3 x ^{2} + 4 x + 2 )}{2 ( y - 1 )}

y^{^{'}} + y = 0, y (1) = 1

x(3y^2-2)y^'(x)-y^3=0,y(1)=2

x (3 y^{2} - 2) y^{^{'}} (x) - y^{3} = 0, y (1) = 2

Frequently Asked Questions (FAQ)

What is the solution for y^'=3xy+5y ?
The solution for y^'=3xy+5y is y=e^{(3x^2)/2+5x+c_{1}}