(dy)/(dx)=(x-2)/(2y^2)

الحلّ

\frac{d y}{d x} = \frac{x - 2}{2 y ^{2}}

خطوات الحلّ

\frac{d y}{d x} = \frac{x - 2}{2 y ^{2}}

Solve separable ODE:

\frac{d y}{d x} = \frac{2 x}{y}

\frac{d y}{d x} - x^{2} y^{2} = x^{2}

y^{^{'}} = \frac{sin ( x )}{y}

\frac{d y}{d t} - 6 y = 5

(1 + t^{2}) \cdot \frac{d y}{d t} = 1 + y^{2}