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Popular >

y^'=3y-4

Solution

y^{^{'}} = 3 y - 4

Solution

y = \frac{e ^{3 t + c_{1}}}{3} + \frac{4}{3}

Solution steps

y^{'} (t) = 3 y - 4

Solve separable ODE:

y = \frac{e ^{3 t + c_{1}}}{3} + \frac{4}{3}

y = \frac{e ^{3 t + c_{1}}}{3} + \frac{4}{3}

Popular Examples

(dy)/(dx)=xsin(y)

\frac{d y}{d x} = x sin (y)

(1+y^2)cos(x)dx-1xdy=0,y(0)= pi/4

(1 + y^{2}) cos (x) d x - 1 x d y = 0, y (0) = \frac{π}{4}

(dy)/(dx)=e^{x-y},y(0)=ln(6)

\frac{d y}{d x} = e^{x - y}, y (0) = ln (6)

xy+(10xy+x)y^'=0

x y + (10 x y + x) y^{^{'}} = 0

(dy)/(dt)=9tsin^2(y),y(-2)= pi/4

\frac{d y}{d t} = 9 t sin^{2} (y), y (- 2) = \frac{π}{4}

Frequently Asked Questions (FAQ)

What is the solution for y^'=3y-4 ?
The solution for y^'=3y-4 is y=(e^{3t+c_{1}})/3+4/3