What is the solution for x^2(xdy+ydx)=9xdy-9ydx ?

The solution for x^2(xdy+ydx)=9xdy-9ydx is y=(c_{1}x)/(x^2-9)

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x^2(xdy+ydx)=9xdy-9ydx

x^{2} (x d y + y d x) = 9 x d y - 9 y d x

y = \frac{c _{1} x}{x ^{2} - 9}

Solution steps

x^{2} (x d y + y d x) = 9 x d y - 9 y d x

Solve separable ODE:

y = \frac{c _{1} x}{x ^{2} - 9}

y = \frac{c _{1} x}{x ^{2} - 9}

\frac{d y}{d x} + 8 y = 0

\frac{\frac{d y}{d x}}{y} = x^{x - 1}

y^{^{'}} + 2 y = 2, 6 sin (3 t) y (0) = 3

3 x \frac{d y}{d x} + 9 x^{3} y = 3 x^{3}

x \frac{d y}{d x} + cot (y) = 0

What is the solution for x^2(xdy+ydx)=9xdy-9ydx ?
The solution for x^2(xdy+ydx)=9xdy-9ydx is y=(c_{1}x)/(x^2-9)