What is the solution for (dy)/(dx)-e^{3x+2y}=0 ?

The solution for (dy)/(dx)-e^{3x+2y}=0 is y=-(ln(-2/3 e^{3x}-c_{1}))/2

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(dy)/(dx)-e^{3x+2y}=0

\frac{d y}{d x} - e^{3 x + 2 y} = 0

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}

Solution steps

\frac{d y}{d x} - e^{3 x + 2 y} = 0

Solve separable ODE:

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}

y y^{^{'}} + 6 x = 0, y (0) = 4

x \frac{d y}{d x} = e^{9 y + x}

\frac{d y}{d t} = \frac{- t}{y}

y^{^{'}} = e^{x} sin (y)

sin (3 x) d x + 2 y cos^{2} (3 x) d y = 0

What is the solution for (dy)/(dx)-e^{3x+2y}=0 ?
The solution for (dy)/(dx)-e^{3x+2y}=0 is y=-(ln(-2/3 e^{3x}-c_{1}))/2