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Popular >

y^'=20y-25

Solution

y^{^{'}} = 20 y - 25

Solution

y = \frac{e ^{20 t + c_{1}}}{4} + \frac{5}{4}

Solution steps

y^{'} (t) = 20 y - 25

Solve separable ODE:

y = \frac{e ^{20 t + c_{1}}}{4} + \frac{5}{4}

y = \frac{e ^{20 t + c_{1}}}{4} + \frac{5}{4}

Popular Examples

\frac{d y}{d x} + k y = 0

(dx)/(dy)=(5y)/(6x)

\frac{d x}{d y} = \frac{5 y}{6 x}

(dy)/(dx)=(1+y^2)/(2y)

\frac{d y}{d x} = \frac{1 + y ^{2}}{2 y}

(dy)/(dt)=-1/50 (y-23)

\frac{d y}{d t} = - \frac{1}{50} (y - 23)

y^'sec(x)=6y^2,y((9pi)/2)= 1/7

y^{^{'}} sec (x) = 6 y^{2}, y (\frac{9 π}{2}) = \frac{1}{7}

Frequently Asked Questions (FAQ)

What is the solution for y^'=20y-25 ?
The solution for y^'=20y-25 is y=(e^{20t+c_{1}})/4+5/4