What is the solution for (dy)/(dt)=-1/50 (y-23) ?

The solution for (dy)/(dt)=-1/50 (y-23) is y=e^{(-t-c_{1})/(50)}+23

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(dy)/(dt)=-1/50 (y-23)

\frac{d y}{d t} = - \frac{1}{50} (y - 23)

y = e^{\frac{- t - c _{1}}{50}} + 23

Solution steps

\frac{d y}{d t} = - \frac{1}{50} (y - 23)

Solve separable ODE:

y = e^{\frac{- t - c _{1}}{50}} + 23

y = e^{\frac{- t - c _{1}}{50}} + 23

y^{^{'}} sec (x) = 6 y^{2}, y (\frac{9 π}{2}) = \frac{1}{7}

(x + 1) d x - y d y = 0

\frac{d y}{d t} + t y = y, y (1) = 3

y^{^{'}} = e^{- y} \frac{x ^{5}}{7}

\frac{d y}{d x} = \frac{2 x}{( y + 1 )}

What is the solution for (dy)/(dt)=-1/50 (y-23) ?
The solution for (dy)/(dt)=-1/50 (y-23) is y=e^{(-t-c_{1})/(50)}+23