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Popular >

y^'=-5xy^2

Solution

y^{^{'}} = - 5 x y^{2}

Solution

y = - \frac{2}{- 5 x ^{2} + c _{1}}

Solution steps

y^{'} (x) = - 5 x y^{2}

Solve separable ODE:

y = - \frac{2}{- 5 x ^{2} + c _{1}}

y = - \frac{2}{- 5 x ^{2} + c _{1}}

Popular Examples

y^{^{'}} - 3 x y = - y

y^'=(9cos(9x))/(3+2y),y(0)=-1

y^{^{'}} = \frac{9 cos ( 9 x )}{3 + 2 y}, y (0) = - 1

(dy)/(dx)y=ln(sqrt(2x+5))

\frac{d y}{d x} y = ln (2 x + 5)

y^{^{'}} = 6 e^{2 x - y}

(dx)/(dt)= 5/(xe^{t+8x)}

\frac{d x}{d t} = \frac{5}{x e ^{t + 8 x}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=-5xy^2 ?
The solution for y^'=-5xy^2 is y=-2/(-5x^2+c_{1)}