What is the solution for (dy)/(dt)+2y=0,y(0)=3 ?

The solution for (dy)/(dt)+2y=0,y(0)=3 is y=3e^{-2t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)+2y=0,y(0)=3

\frac{d y}{d t} + 2 y = 0, y (0) = 3

y = 3 e^{- 2 t}

Solution steps

\frac{d y}{d t} + 2 y = 0

Solve separable ODE:

y = 3 e^{- 2 t}

y = 3 e^{- 2 t}

\frac{d y}{d x} + 6 x^{2} y = 5 x^{2}, y (0) = 4

y^{^{'}} = x y - 2 x + y - 2

\frac{d y}{d x} = \frac{x + 1}{e ^{y}}, y (0) = 2

y^{^{'}} = \frac{2}{3} x 1 - 9 y^{2}, y (0) = 0

(x + 1) y^{^{'}} - 3 y = 0

What is the solution for (dy)/(dt)+2y=0,y(0)=3 ?
The solution for (dy)/(dt)+2y=0,y(0)=3 is y=3e^{-2t}