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Popular Calculus >

y^'=xy-2x+y-2

Solution

y^{^{'}} = x y - 2 x + y - 2

Solution

y = e^{\frac{x ^{2}}{2} + x + c_{1}} + 2

Solution steps

y^{'} (x) = x y - 2 x + y - 2

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + x + c_{1}} + 2

y = e^{\frac{x ^{2}}{2} + x + c_{1}} + 2

Graph

Popular Examples

(dy)/(dx)=(x+1)/(e^y),y(0)=2

\frac{d y}{d x} = \frac{x + 1}{e ^{y}}, y (0) = 2

y^'= 2/3 xsqrt(1-9y^2),y(0)=0

y^{^{'}} = \frac{2}{3} x 1 - 9 y^{2}, y (0) = 0

(x + 1) y^{^{'}} - 3 y = 0

y^'=3x^2y^2,y(-1)=a,y(0)=1

y^{^{'}} = 3 x^{2} y^{2}, y (- 1) = a, y (0) = 1

(dy)/(dx)=(xy-4x+y-4)/(xy-6x-3y+18)

\frac{d y}{d x} = \frac{x y - 4 x + y - 4}{x y - 6 x - 3 y + 18}

Frequently Asked Questions (FAQ)

What is the solution for y^'=xy-2x+y-2 ?
The solution for y^'=xy-2x+y-2 is y=e^{(x^2)/2+x+c_{1}}+2