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Popular >

y^'=xy-2x+y-2

Solution

y^{^{'}} = x y - 2 x + y - 2

Solution

y = e^{\frac{x ^{2}}{2} + x + c_{1}} + 2

Solution steps

y^{'} (x) = x y - 2 x + y - 2

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + x + c_{1}} + 2

y = e^{\frac{x ^{2}}{2} + x + c_{1}} + 2

Popular Examples

(dy)/(dx)=(x+1)/(e^y),y(0)=2

\frac{d y}{d x} = \frac{x + 1}{e ^{y}}, y (0) = 2

y^'= 2/3 xsqrt(1-9y^2),y(0)=0

y^{^{'}} = \frac{2}{3} x 1 - 9 y^{2}, y (0) = 0

(x + 1) y^{^{'}} - 3 y = 0

(dy)/(dx)x^2+y^2=77

\frac{d y}{d x} x^{2} + y^{2} = 77

(dy)/(dx)=sec(y)

\frac{d y}{d x} = sec (y)

Frequently Asked Questions (FAQ)

What is the solution for y^'=xy-2x+y-2 ?
The solution for y^'=xy-2x+y-2 is y=e^{(x^2)/2+x+c_{1}}+2