What is the solution for 3dx+ydy=0 ?

The solution for 3dx+ydy=0 is y=sqrt(-6x+c_{1)},y=-sqrt(-6x+c_{1)}

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3dx+ydy=0

3 d x + y d y = 0

y = - 6 x + c_{1}, y = - - 6 x + c_{1}

Solution steps

3 d x + y d y = 0

Solve separable ODE:

y = - 6 x + c_{1}, y = - - 6 x + c_{1}

y = - 6 x + c_{1}, y = - - 6 x + c_{1}

\frac{d y}{d x} = \frac{x y - 4 x + y - 4}{x y - 6 x - 3 y + 18}

\frac{d y}{d x} = x^{2} (y - 2), y (0) = 4

y^{^{'}} = e^{- y}, y (0) = 0

\frac{d y}{d x} = \frac{2}{3} x 1 - 9 y^{2}, y (0) = 0

\frac{d v}{d t} = \frac{2}{9} v

What is the solution for 3dx+ydy=0 ?
The solution for 3dx+ydy=0 is y=sqrt(-6x+c_{1)},y=-sqrt(-6x+c_{1)}