What is the solution for y^'=y-(1/1000)y^2 ?

The solution for y^'=y-(1/1000)y^2 is y=-(1000e^{t+c_{1}})/(1-e^{t+c_{1)}}

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y^'=y-(1/1000)y^2

y^{^{'}} = y - (\frac{1}{1000}) y^{2}

y = - \frac{1000 e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

Solution steps

y^{'} (t) = y - (\frac{1}{1000}) y^{2}

Solve separable ODE:

y = - \frac{1000 e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

y = - \frac{1000 e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

\frac{d y}{d x} = cos^{2} (x) cos^{2} (2 y)

y^{^{'}} = \frac{x}{y}, y (0) = 0

y^{^{'}} = \frac{7 x ^{2} - 1}{7 + 5 y}

y^{^{'}} = \frac{x ( 1 + y ^{2} )}{4 y}

\frac{d y}{d x} y = (ln (x))^{l n (x)}

What is the solution for y^'=y-(1/1000)y^2 ?
The solution for y^'=y-(1/1000)y^2 is y=-(1000e^{t+c_{1}})/(1-e^{t+c_{1)}}