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Popular >

2yy^'=15t^2,y(0)=4

Solution

2 y y^{^{'}} = 15 t^{2}, y (0) = 4

Solution

y = 5 t^{3} + 16

Solution steps

2 y y^{'} (t) = 15 t^{2}

Solve separable ODE:

y = 5 t^{3} + 16

y = 5 t^{3} + 16

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Frequently Asked Questions (FAQ)

What is the solution for 2yy^'=15t^2,y(0)=4 ?
The solution for 2yy^'=15t^2,y(0)=4 is y=sqrt(5t^3+16)